zig/test/cases/const_slice_child.zig
Andrew Kelley fcbb7426fa use * for pointer type instead of &
See #770

To help automatically translate code, see the
zig-fmt-pointer-reform-2 branch.

This will convert all & into *. Due to the syntax
ambiguity (which is why we are making this change),
even address-of & will turn into *, so you'll have
to manually fix thes instances. You will be guaranteed
to get compile errors for them - expected 'type', found 'foo'
2018-05-31 17:28:07 -04:00

45 lines
975 B
Zig

const debug = @import("std").debug;
const assert = debug.assert;
var argv: *const *const u8 = undefined;
test "const slice child" {
const strs = ([]*const u8){
c"one",
c"two",
c"three",
};
argv = &strs[0];
bar(strs.len);
}
fn foo(args: [][]const u8) void {
assert(args.len == 3);
assert(streql(args[0], "one"));
assert(streql(args[1], "two"));
assert(streql(args[2], "three"));
}
fn bar(argc: usize) void {
const args = debug.global_allocator.alloc([]const u8, argc) catch unreachable;
for (args) |_, i| {
const ptr = argv[i];
args[i] = ptr[0..strlen(ptr)];
}
foo(args);
}
fn strlen(ptr: *const u8) usize {
var count: usize = 0;
while (ptr[count] != 0) : (count += 1) {}
return count;
}
fn streql(a: []const u8, b: []const u8) bool {
if (a.len != b.len) return false;
for (a) |item, index| {
if (b[index] != item) return false;
}
return true;
}