zig/test/cases/enum_with_members.zig
Andrew Kelley fcbb7426fa use * for pointer type instead of &
See #770

To help automatically translate code, see the
zig-fmt-pointer-reform-2 branch.

This will convert all & into *. Due to the syntax
ambiguity (which is why we are making this change),
even address-of & will turn into *, so you'll have
to manually fix thes instances. You will be guaranteed
to get compile errors for them - expected 'type', found 'foo'
2018-05-31 17:28:07 -04:00

28 lines
732 B
Zig

const assert = @import("std").debug.assert;
const mem = @import("std").mem;
const fmt = @import("std").fmt;
const ET = union(enum) {
SINT: i32,
UINT: u32,
pub fn print(a: *const ET, buf: []u8) error!usize {
return switch (a.*) {
ET.SINT => |x| fmt.formatIntBuf(buf, x, 10, false, 0),
ET.UINT => |x| fmt.formatIntBuf(buf, x, 10, false, 0),
};
}
};
test "enum with members" {
const a = ET{ .SINT = -42 };
const b = ET{ .UINT = 42 };
var buf: [20]u8 = undefined;
assert((a.print(buf[0..]) catch unreachable) == 3);
assert(mem.eql(u8, buf[0..3], "-42"));
assert((b.print(buf[0..]) catch unreachable) == 2);
assert(mem.eql(u8, buf[0..2], "42"));
}